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0.5x^2+x-2=-0.2x+1
We move all terms to the left:
0.5x^2+x-2-(-0.2x+1)=0
We get rid of parentheses
0.5x^2+x+0.2x-1-2=0
We add all the numbers together, and all the variables
0.5x^2+1.2x-3=0
a = 0.5; b = 1.2; c = -3;
Δ = b2-4ac
Δ = 1.22-4·0.5·(-3)
Δ = 7.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.2)-\sqrt{7.44}}{2*0.5}=\frac{-1.2-\sqrt{7.44}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.2)+\sqrt{7.44}}{2*0.5}=\frac{-1.2+\sqrt{7.44}}{1} $
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